100x^2+482x-45=0

Solution for 100x^2+482x-45=0 equation:

100x^2+482x-45=0

a = 100; b = 482; c = -45;
Δ = b2-4ac
Δ = 4822-4·100·(-45)
Δ = 250324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{250324}=\sqrt{4*62581}=\sqrt{4}*\sqrt{62581}=2\sqrt{62581}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(482)-2\sqrt{62581}}{2*100}=\frac{-482-2\sqrt{62581}}{200}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(482)+2\sqrt{62581}}{2*100}=\frac{-482+2\sqrt{62581}}{200}
$